The reaction `CH_(2) = CHCH_(3) + HBr rarr CH_(3)CHBrCH_(3)` is -

Options

A. Nucleophilic addition
B. Electrophilic addition
C. Electrophilic substitution
D. Free radical addition

Answer

To determine the type of reaction represented by the equation `CH₂=CHCH₃ + HBr → CH₃CHBrCH₃`, we can analyze the process step by step.

### Step-by-Step Solution:

1. **Identify the Reactants**:
The reactants in the equation are propene (`CH₂=CHCH₃`) and hydrogen bromide (HBr).

2. **Recognize the Type of Reaction**:
The reaction involves the addition of HBr to the alkene (propene). This is an addition reaction where HBr adds across the double bond of the alkene.

3. **Mechanism of the Reaction**:
- **Electrophilic Addition**: In this reaction, the double bond in propene acts as a nucleophile (electron-rich site) and attacks the electrophile (H⁺ from HBr).
- **Formation of Carbocation**: When H⁺ adds to one of the carbons of the double bond, it generates a carbocation. The more stable carbocation will form, which in this case is a secondary carbocation at the second carbon (C2) due to the presence of two alkyl groups (CH₃).
- **Nucleophilic Attack by Bromide Ion**: The bromide ion (Br⁻) then attacks the positively charged carbon (the carbocation), resulting in the formation of the product.

4. **Product Formation**:
The product formed is 2-bromopropane (`CH₃CHBrCH₃`), where bromine has added to the carbon that was part of the carbocation.

5. **Conclusion**:
Since the reaction involves the addition of HBr to an alkene, it is classified as an **Electrophilic Addition Reaction**.

### Final Answer:
The reaction `CH₂=CHCH₃ + HBr → CH₃CHBrCH₃` is an **Electrophilic Addition Reaction**.

---