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Let f:R to R be a function satisfying f...

Let `f:R to R ` be a function satisfying `f(2-x)=f(2+x) and f(20-x)=f(x) AA x in R.` For this function `f`, answer the following.
If `f(2) ne f(6),` then the

A

(a) fundamental period of `f(x) " is " 1`

B

(b) fundamental period of `f(x) " may be " 1`

C

(c) period of `f(x)` cannot be 1

D

(d) fundamental period of `f(x) " is " 8`

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To solve the problem, we need to analyze the given functional equations step by step. ### Step 1: Analyze the first functional equation We start with the equation: \[ f(2 - x) = f(2 + x) \] This equation implies that the function \( f \) is symmetric about \( x = 2 \). ### Step 2: Substitute \( x \) with \( 2 - x \) Let's replace \( x \) in the first equation with \( 2 - x \): \[ f(2 - (2 - x)) = f(2 + (2 - x)) \] This simplifies to: \[ f(x) = f(4 - x) \] This means that the function is also symmetric about \( x = 4 \). ### Step 3: Analyze the second functional equation Now, consider the second functional equation: \[ f(20 - x) = f(x) \] This indicates that the function \( f \) is symmetric about \( x = 10 \). ### Step 4: Combine the results From the first equation, we have: 1. \( f(x) = f(4 - x) \) 2. \( f(x) = f(20 - x) \) ### Step 5: Find the period of the function We can use the symmetry properties to find the period of the function. From \( f(x) = f(20 - x) \), if we replace \( x \) with \( x + 20 \): \[ f(x + 20) = f(20 - (x + 20)) = f(-x) \] But since \( f(x) = f(20 - x) \), this means: \[ f(x + 20) = f(x) \] Thus, the function has a period of 20. ### Step 6: Check for smaller periods Next, we need to check if there is a smaller period. We know: - From \( f(x) = f(4 - x) \), we can check if there is a period of 8: \[ f(x + 8) = f(4 - (x + 8)) = f(-4 - x) \] This does not simplify back to \( f(x) \). ### Conclusion Since we have established that the function is symmetric about \( x = 10 \) and \( x = 4 \), and we found that the period is 20, we conclude that the period of the function \( f \) is 20. ### Final Answer Thus, if \( f(2) \neq f(6) \), then the period of the function \( f \) is: \[ \text{Period} = 20 \] ---

To solve the problem, we need to analyze the given functional equations step by step. ### Step 1: Analyze the first functional equation We start with the equation: \[ f(2 - x) = f(2 + x) \] This equation implies that the function \( f \) is symmetric about \( x = 2 \). ### Step 2: Substitute \( x \) with \( 2 - x \) ...
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