The velocity of a particle moving in a straight line is directly proportional to `3//4th` power of time elapsed. How does its displacement and acceleration depend on time?

Options

A. Increasing acceleration
B. Decreasing acceleration
C. Increasing retardation
D. Decreasing retardation

Answer

D

Explanation

`s=kt^(1//2) rArr a(d^(2)s)/(dt^(2))=-(1)/(4) kt ^(-3//2)`
As `t` increase, retardation decrases.