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When the speed of a car is u, the mimimu...

When the speed of a car is `u`, the mimimum distance over which it canbe stopped is `a`, If speed becomes `nu`, what will be the mimimum distance over which it can be stopped during the same time?

A

` s//h`

B

` ns`

C

` s//n^(2)`

D

`n^(2) s`

Text Solution

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The correct Answer is:
To solve the problem, we need to analyze the stopping distance of a car when its speed changes. ### Step-by-Step Solution: 1. **Understanding the Given Information**: - When the speed of the car is \( u \), the minimum stopping distance is \( a \). - We need to find the stopping distance when the speed becomes \( nu \) (where \( n \) is a constant multiplier). 2. **Using the Formula for Stopping Distance**: - The stopping distance \( S \) can be calculated using the formula: \[ S = \frac{u^2}{2a} \] - Here, \( u \) is the initial speed, and \( a \) is the deceleration (retardation). 3. **Finding the Stopping Distance for Speed \( nu \)**: - When the speed is \( nu \), the stopping distance \( S' \) can be expressed as: \[ S' = \frac{(nu)^2}{2a'} \] - Here, \( a' \) is the deceleration when the speed is \( nu \). 4. **Relating the Deceleration**: - Since the time taken to stop is the same in both cases, we can relate the decelerations. - The time \( t \) to stop from speed \( u \) is: \[ t = \frac{u}{a} \] - The time \( t \) to stop from speed \( nu \) is: \[ t = \frac{nu}{a'} \] - Setting these equal gives: \[ \frac{u}{a} = \frac{nu}{a'} \] - Rearranging this gives: \[ a' = \frac{a}{n} \] 5. **Substituting Back into the Stopping Distance Formula**: - Now substitute \( a' \) back into the stopping distance formula for \( nu \): \[ S' = \frac{(nu)^2}{2 \cdot \frac{a}{n}} = \frac{n^2 u^2}{\frac{2a}{n}} = \frac{n^3 u^2}{2a} \] 6. **Relating to the Original Stopping Distance**: - From the original stopping distance \( a = \frac{u^2}{2a} \), we can express \( \frac{u^2}{2a} \) as \( a \). - Thus, we can rewrite \( S' \) in terms of \( a \): \[ S' = n^2 a \] ### Final Result: The minimum distance over which the car can be stopped when its speed becomes \( nu \) is: \[ S' = n^2 a \]

To solve the problem, we need to analyze the stopping distance of a car when its speed changes. ### Step-by-Step Solution: 1. **Understanding the Given Information**: - When the speed of the car is \( u \), the minimum stopping distance is \( a \). - We need to find the stopping distance when the speed becomes \( nu \) (where \( n \) is a constant multiplier). ...
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