A moving car possesses average velocities of `5 m s^(-1), 10 m s^(-1)`, and `15 m s^(-1)`, in the first, second, and third seconds, respecticely. What is the total destance coverd by the car in these `3 s`.?

Options

A. `15 m`
B. `30`
C. `55 m`
D. `None of these

Explanation

To solve the problem, we need to calculate the total distance covered by the car in three seconds, given the average velocities for each second.

### Step-by-Step Solution:

1. **Identify the average velocities for each second:**
- First second: \( v_1 = 5 \, \text{m/s} \)
- Second second: \( v_2 = 10 \, \text{m/s} \)
- Third second: \( v_3 = 15 \, \text{m/s} \)

2. **Calculate the distance covered in each second:**
- Distance covered in the first second (\( d_1 \)):
\[ d_1 = v_1 \times t_1 = 5 \, \text{m/s} \times 1 \, \text{s} = 5 \, \text{m} \]
- Distance covered in the second second (\( d_2 \)):
\[ d_2 = v_2 \times t_2 = 10 \, \text{m/s} \times 1 \, \text{s} = 10 \, \text{m} \]
- Distance covered in the third second (\( d_3 \)):
\[ d_3 = v_3 \times t_3 = 15 \, \text{m/s} \times 1 \, \text{s} = 15 \, \text{m} \]

3. **Sum the distances to find the total distance covered:**
\[ \text{Total distance} = d_1 + d_2 + d_3 = 5 \, \text{m} + 10 \, \text{m} + 15 \, \text{m} = 30 \, \text{m} \]

4. **Conclusion:**
The total distance covered by the car in 3 seconds is \( 30 \, \text{m} \).

### Final Answer:
The total distance covered by the car in these 3 seconds is **30 meters**.

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