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The pressure-volume of various thermodyn...

The pressure-volume of various thermodynamic process is shown in graphs:

Work is the mole of transference of energy. It has been observed that reversible work done by the system is the maximum obtainable work.
`w_(rev) gt w_(irr)`
The works of isothermal and adiabatic processes are different from each other.
`w_("isothermal reversible") = 2.303 nRT log_(10) ((V_(2))/(V_(1)))`
`= 2.303 nRT log_(10)((P_(2))/(P_(1)))`
`w_("adiabatic reversible") = C_(V) (T_(1)-T_(2))`
A thermodynamic system goes in a cyclic process as represented in the following `P -V` diagram:

The net work done during the complete cycle is given by the area

A

|z|=5

B

|z|lt 5

C

|z| gt5

D

2 lt |z| lt 3

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B, D
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The pressure-volume of varies thermodynamic process is shown in graphs: Work is the mole of transference of energy. It has been observed that reversible work done by the system is the maximum obtainable work. w_(rev) gt w_(irr) The works of isothermal and adiabatic processes are different from each other. w_("isothermal reversible") = 2.303 nRT log_(10) ((V_(2))/(V_(1))) = 2.303 nRT log_(10)((P_(2))/(P_(1))) w_("adiabatic reversible") = C_(V) (T_(1)-T_(2)) A thermodynamic system goes in a cyclic process as represented in the following P -V diagram: The network done during the complete cycle is given by the area

The pressure-volume of varies thermodynamic process is shown in graphs: Work is the mole of transference of energy. It has been observed that reversible work done by the system is the maximum obtainable work. w_(rev) gt w_(irr) The works of isothermal and adiabatic processes are different from each other. w_("isothermal reversible") = 2.303 nRT log_(10) ((V_(2))/(V_(1))) = 2.303 nRT log_(10)((P_(2))/(P_(1))) w_("adiabatic reversible") = C_(V) (T_(1)-T_(2)) P-V plots for two gases during adiabatic processes are given in the given figure: Plot D and Plot C should correspond to

The pressure-volume of varies thermodynamic process is shown in graphs: Work is the mole of transference of energy. It has been observed that reversible work done by the system is the maximum obtainable work. w_(rev) gt w_(irr) The works of isothermal and adiabatic processes are different from each other. w_("isothermal reversible") = - 2.303 nRT log_(10) ((V_(2))/(V_(1))) = 2.303 nRT log_(10)((P_(2))/(P_(1))) w_("adiabatic reversible") = C_(V) (T_(1)-T_(2)) Calculate work done when 1 mole of an ideal gas is expanded reversibly from 30L to 60L at a constant temperature of 300K

The pressure-volume of varies thermodynamic process is shown in graphs: Work is the mole of transference of energy. It has been observed that reversible work done by the system is the maximum obtainable work. w_(rev) gt w_(irr) The works of isothermal and adiabatic processes are different from each other. w_("isothermal reversible") = 2.303 nRT log_(10) ((V_(2))/(V_(1))) = 2.303 nRT log_(10)((P_(2))/(P_(1))) w_("adiabatic reversible") = C_(V) (T_(1)-T_(2)) If w_(1),w_(2),w_(3) and w_(4) are work done in isothermal, adiabatic, isobaric, and isochoric reversible processes, respectively then the correct sequence (for expansion) would be

The pressure-volume of varies thermodynamic process is shown in graphs: Work is the mole of transference of energy. It has been observed that reversible work done by the system is the maximum obtainable work. w_(rev) gt w_(irr) The works of isothermal and adiabatic processes are different from each other. w_("isothermal reversible") = 2.303 nRT log_(10) ((V_(2))/(V_(1))) = 2.303 nRT log_(10)((P_(2))/(P_(1))) w_("adiabatic reversible") = C_(V) (T_(1)-T_(2)) The q value and work done in isothermal reversible expansion of one mole of an ideal gas from initial pressure of 1 bar to final pressure of 0.1 bar at constant temperature 273K are:

if work is done by the system then W is

P – V graph for a cyclic process is shown in figure . Work done is given by

The work done by 1 mole of ideal gas during an adiabatic process is (are ) given by :

Work done in reversible isothermal expansion is given by

A thermodynamic system goes from states (i) P_(1),V to 2P_(1),V (ii) P,V_(1) to P2 ,V_(1) . Then work done in the two cases is

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