`sqrt(ax+b)`

Explanation

`int sqrt(ax+b)dx" माना "ax+b=t`
`=intsqrtt (dt)/(a)=(1)/(a).intt^(1//2)dt" "rArr dx=dt`
`=(1)/(a).(t^(3//2))/(3//2)+c" "rArr dx=(dt)/(a)`
`=(2)/(3a)(ax+b)^(3//2)+c`