`xsqrt(1+2x^(2))`

Explanation

`intxsqrt(1+2x^(2))dx" माना "1+2x^(2)=t`
`=intsqrtt (dt)/(4)=(1)/(4).(t^(3//2))/(3//2)+c" "rArr 4xdx=dt`
`=(1)/(6)(1+2x^(2))^(3//2)+c" "rArr" "xdx =(dt)/(4)`