`int (1)/(x-sqrtx) dx`

Explanation

`int(1)/(x-sqrtx)dx" माना "sqrtx-1=t`
`=int(1)/(sqrtx(sqrtx-1))dx" "rArr (1)/(2sqrtx)dx=dt`
`=int(2dt)/(t)" "rArr (1)/(sqrtx)dx=2dt`
`=2log|t|+c=2log|sqrtx-1|+c`