`int(x)/(sqrt(x+4))dx`

Explanation

`(x)/(sqrt(x+4))dx" माना "x+4=t^(2)`
`=int((t^(2)-4).2tdt)/(sqrt(t^(2)))=2int(t^(2)-4)dt" "rArr dx=2tdt`
`=2[(t^(3))/(3)-4t]+c`
`=(2)/(3)(x+4)^(3//2)-8(x+4)^(1//2)+c`