`(x^(3)-1)^((1)/(3))x^(5)`

Explanation

`int(x^(3)-1)^(1//3)x^(5)dx" माना "x^((3)-1=t`
`=int(x^(3)-1)^(1//3)x^(5)dx" माना "x^(3)-1=t`
`=int(x^(3)-1)^(1//3).x^(3).x^(2)dx" "rArr 3x^(2)dx=dt`
`=int t^(1//3)(t+1)(dt)/(3)" "rArr x^(2)dx=(dt)/(3)`
`=(1)/(3)int t^(4//3)dt+(1)/(3)intt^(1//3)dt`
`=(1)/(3).(t^(7//3))/(7//3)+(1)/(3).(t^(4//3))/(4//3)+c`
`=(1)/(7)(x^(3)-1)^(7//3)+(1)/(4)(x^(3)-1)^(4//3)+c`