`int (1)/(x(logx)^(m) )dx,x gt 0, m ne 1`

Explanation

`int(1)/(x(logx)^(m))dx" माना "logx=t`
`=int(1)/(t^(m))dt=intt^(-m)dt" "rArr (1)/(x)dx=dt`
`=(t^(-m+1))/(-m+1)+c=((logx)^(1-m))/(1-m)+c`