`(x)/(e^(x^(2)))`

Explanation

`int(x)/(e^(x^(2)))dx" माना "-x^(2)=t` ltrgt `=intx.e^(-x^(2))dx=inte^(t).(dt)/(-2)" "rArr -2xdx=dt`
`=-(1)/(2)e^(t)+c=-(1)/(2)e^(-x^(2))+c" "rArr xdx=(dt)/(-2)`