`int(2cosx-3sinx)/(6cosx+4 sinx)dx`

Explanation

`int(2cos x-3 sinx)/(6 cosx+4 sinx)dx`
माना `3cosx+2sinx=t`
`rArr (-3 sin x+2 cos x)dx=dt`
`=(1)/(2)int(2cosx-3sinx)/(3cosx+2sinx)dx`
`=(1)/(2)int(1)/(t)dt`
`=(1)/(2)log|t|+c`
`=(1)/(2)log|3 cos x+2 sinx|+c`