`sqrt(sin2x)cos 2x`

Explanation

`intsqrt(sin 2x)cos 2xdx" माना "sin 2x = t`
`=int sqrtt (dt)/(2)" "rArr 2 cos 2x dx = dt`
`" "rArr cos 2x dx =(dt)/(2)`
`=(1)/(2).(t^(3//2))/(3//2)+c=(1)/(3)(sin 2x)^(3//2)+c`