`(cos sqrtx)/(sqrt(1+sinx))`

Explanation

`int(cosx)/(sqrt(1+sinx))dx" माना "1+sinx=t`
`" "rArr" "cos x dx = dt`
`=int(1)/(sqrtt)dt=int t^(-1//2)dt`
`=(t^(1//2))/(1//2)+c=2sqrt(1+sinx)+c`