`((1+logx)^(2))/(x)`

Explanation

`int((1+logx)^(2))/(x)dx" माना "1+logx=t`
`" "rArr" "(1)/(x)dx=dt`
`=intt^(2)dt=(1)/(3)t^(3)+c`
`=(1)/(3)(1+logx)^(3)+c`