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NCERT Solutions
Class 8
Maths
Chapter 5 Number Play
Exercise 5.3

NCERT Class 8 Maths Ch. 5 Number Play Other Exercises:-

Exercise 5.1

Exercise 5.2

Exercise 5.3

Exercise 5.4


NCERT Solutions Class 8 Maths All Chapters:-

Chapter 1 - A Square and a Cube

Chapter 2 - Power play

Chapter 3 - A story of Numbers

Chapter 4 - Quadrilaterals

Chapter 5 - Number Play

Chapter 6 - We distibute, yet thinmgs multiply

Chapter 7 - Proportional Reasoning

Frequently Asked Questions

For a 3 x 3 magic square using numbers 1 to 9, the total sum of all numbers is 45. Since there are 3 rows, each row must sum to 45 / 3 = 15.

Rules for 3 and 9 depend on the fact that 10 - 1 and 100 - 1 are multiples of 9. For 11, we use the fact that 10 + 1 and 100 - 1 are multiples of 11, which creates the "alternating" plus and minus pattern.

Yes. In divisibility tests, we look at the absolute difference. If the difference is -11, 0, 11, 22, etc., the number is divisible by 11.

Magic squares can be constructed for any n x n grid except for 2 x 2.

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NCERT Solutions for Class 8 Maths Chapter 5 Number Play - Exercise 5.3

Mastering complex number patterns is simple with our NCERT Solutions for Class 8 Maths Ch 5: Playing with Numbers – Exercise 5.3. This exercise expands your toolkit to include the divisibility rules for 2, 5, 10, and the "alternating sum" rule for 11. You will also learn the logic behind constructing 3x3 Magic Squares where every row, column, and diagonal adds up to the same constant.

Class 8 Math Lessons (Ch 5): Learn to Solve Advanced Number Puzzles with Ease! The solutions to Exercise 5.3 will be presented in a step-by-step approach to help students identify multiples of 11 and complete magic grids. These solutions are in accordance with the CBSE Guidelines to improve logical reasoning and pattern recognition. Additionally, these solutions build the foundation for number theory and computer science algorithms.

1.0Download Class 8 Maths Chapter 5 Number Play Ex 5.3 NCERT Solutions PDF

Chapter 5 of our simple NCERT Solutions for Class 8 Maths You may download the PDF for Exercise 5.3. Ideal for fast reference and offline study.

NCERT Solutions Class 8 Maths Chapter 5 Ex 5.3

Download PDF

2.0 Detailed NCERT Class 8 Maths Chapter 5 Solutions of Exercise 5.3

1.The digital root of an 8-digit number is 5 . What will be the digital root of 10 more than that number?

Sol. Consider the 8-digit number 80000006. The digital root of 80000006=8+0+0+ 0+0+0+0+6 = 14 =1+4 =5 10 more than 80000006=80000006+10 =80000016 The digital root of 80000016=8+0+0+ 0+0+0+1+6 = 15 =1+5 =6 Thus, the digital root of 10 more than 80000006 is 6 .

2. Write any number. Generate a sequence of numbers by repeatedly adding 11 . What would be the digital roots of this sequence of numbers? Share your observations. Sol. Consider the number =40 The sequence of numbers by repeatedly adding 11 are 40,51(40+11),62(51+ 11), 73(62+11),84(73+11),95(84+ 11), 106(95+11),117(106+11), 128(117+11),139(128+11), etc. The digital roots of this sequence of numbers are: 40=4+0=4; 51=5+1=6; 62=6+2=8; 73=7+3=10=1+0=1; 84=8+4=12=1+2=3; 95=9+5=14=1+4=5; 106=1+0+6=7; 117=1+1+7=9; 128=1+2+8=11=1+1=2; 139=1+3+9=13=1+3=4,... etc. Thus, the digital roots of this sequence of numbers are 4,6,8,1,3,5,7,9,2,4,……. Observations: The digital roots are 4,6,8,1,3,5,7,9,2, 4,...... This sequence starts repeating after 9 steps. So the digital roots form a cycle: 4,6,8,1, 3,5,7,9,2,4,…….

3. What will be the digital root of the number 9a+36b+13 ? Sol. First Method: The digital root of the number 9a+36 b+13=9a+36 b+9+4 =9(a+4 b+1)+4 =9+4 =13[∵ The digital root of multiples of 9 is always 9.] =1+3=4

Thus, the digital root of the number 9a + 36 b+13 will be 4 .

Second Method: We have 9a+36b+13 Here, a and b are integers Put a=1, b=1, 9a+36b+13=9×1+36×1+13 =9+36+13 =58 The digital root of 58=5+8=13=1+3 = 4

Put a=2,6=3, 9a+36b+13=9×2+36×3+13 =18+108+13 = 139 The digital root of 139=1+3+9=13=1 +3=4 Thus, the expression 9a + 36b + 13 always has a digital root of 4 .

4. Make conjectures by examining if there are any patterns or relations between (i) the parity of a number and its digital root. (ii) the digital root of a number and the remainder obtained when the number is divided by 3 or 9 .

Sol. Consider the pattern: 8,16,24,32,40,……. (i) 8=8= digital root, parity → even 16=1+6=7= digital root, parity → odd 24=2+4=6= digital root, parity → even 32=3+2=5= digital root, parity → odd 40=4+0=4= digital root, parity → even (ii) Divided by 3 8÷3⇒2, Remainder 24÷3⇒0, Remainder 32÷3⇒2, Remainder 40÷3⇒1, Remainder Divided by 9 8÷9⇒8, Remainder 24÷9⇒6, Remainder 32÷9⇒5, Remainder 40÷9⇒4, Remainder

3.0Key Concepts of Chapter 5 Number Play Exercise 5.3

  • Divisibility by 10 and 5: Focuses on the unit's digit (0 for 10; 0 or 5 for 5).
  • Divisibility by 2: Focuses on the unit's digit being even (0, 2, 4, 6, 8).
  • Divisibility by 11: A number is divisible by 11 if the difference between the sum of digits at odd places and the sum of digits at even places is either 0 or a multiple of 11.
  • Magic Squares: A square grid where the sum of numbers in each row, each column, and both main diagonals is the same (the Magic Constant).

4.0NCERT Solutions for Class 8 Maths Chapter 5 Number Play : All Exercises

NCERT Solutions for Class 8 Maths Chapter 5 Number Play - Exercise 5.1

NCERT Solutions for Class 8 Maths Chapter 5 Number Play - Exercise 5.2

NCERT Solutions for Class 8 Maths Chapter 5 Number Play - Exercise 5.3

NCERT Solutions for Class 8 Maths Chapter 5 Number Play - Exercise 5.4

5.0Benefits of NCERT Solutions for Class 8 Maths Chapter 5 Exercise 5.3

  • Conceptual Clarity: Provides a logical explanation for the "jump-step" method used for 11.
  • Brain Training: Magic squares improve mental addition and spatial reasoning.
  • Exam-Oriented: Covers the "find the missing digit for divisibility by 11" which is a common competitive exam question.