Geometry is based on triangles, which are polygons with three sides and three angles. They appear to be used in many aspects of mathematics and daily life, from calculating areas and distances to designing structures. We provide you with these comprehensive notes on triangles because of the shape's widespread use and importance in geometry. So let's begin!
A triangle is a two-dimensional polygonal shape of geometry with three sides, three angles, and three vertices. It is one of the most basic shapes of geometry, but the most stable form, which is why it is a commonly applied shape in architecture and engineering. In solving problems involving triangles, it is represented by the symbol .
Triangles according to the side length and angle measure can be categorised into six most common types, which are:
All triangles have some common as well as individual properties depending on their type. Some of them are:
A + B + C = 180°
A + B = E
a+b>c or a+c>b or b+c>a
This is a property of a right triangle, better known as Pythagoras' theorem, and formulated as:
a2 + b2 = c2
The perimeter of any geometrical figure is nothing but the sum of all the sides of the figure. Therefore, the perimeter of a triangle is also the sum of all its three sides, a, b, and c, and the formula for the same can be written as:
Perimeter of a Triangle = a + b + c
Area is the region covered by a geometric shape. For a triangle, it is the region covered by its three sides.
Area of Triangle= 12BaseHeight
Area of Triangle=s(s-a)(s-b)(s-c)
\text{Area of Triangle} = \sqrt{s(s - a)(s - b)(s - c)}
Where s is the semiperimeter of the triangle, that is:
s = a+b+c2
Area of Triangle = 12[x1(y2-y3)+x2(y3-y1)+x3(y1-y2)]
Where (x1,y1), (x2,y2), and (x3,y3) are the appropriate vertices of a triangle located on the Cartesian plane.
Problem 1: The angles of a triangle are in the ratio 2:3:4. Find all the angles.
Solution: Let the angles of the triangle be 2x, 3x, and 4x.
Now, using the angle sum property of triangles:
A + B + C = 180°
2x + 3x + 4x = 180°
9x = 180°
x = 20°
Therefore, all the angles of triangles will be:
Problem 2: In an isosceles triangle, the vertex angle is 40°. Determine the base angles.
Solution: According to the property of an isosceles triangle, the base angles are equal to each other in measurement. Therefore, the base angles are B = C = x.
Now, using the angle sum property:
A + B + C = 180°
40 + x + x = 180°
2x = 180° – 40° = 140°
x = 70°
Hence, the base angles for the given triangle are 70° each.
Problem 3: A triangle with sides 13 cm, 14 cm, and 15 cm. What is the height from the side that measures 14 cm?
Solution: According to the question:
The semiperimeter of the triangle(s) = 13+15+142 =21
Now, using Heron’s formula for the area of a triangle(A): s(s-a)(s-b)(s-c)
A=21(21-13)(21-14)(21-15)
A=21876=84cm2
Now, using the base and height formula of the area of a triangle, along a 14cm base:
Area of Triangle= 12BaseHeight
84= 1214Height
Height=12cm
(Session 2026 - 27)