Exercise 2.2 is focused on practicing expressions in real-life situations. It shows how expressions can be built from everyday problems and how we can solve them by substituting out the variable for a number to develop your ability to understand how to use algebra and answer basic questions.
This exercise aligns with the new NCERT syllabus and is a topic in the CBSE Maths curriculum. It helps learn to understand how to read a word problem to be able to turn it into a mathematical expression. The NCERT Solutions provided on this page make the questions easy to understand through clear steps combined with simple language.
Practicing this exercise can help you become a better thinker and faster in your ability to solve all the same kinds of questions. The topic of arithmetic expressions is important if you are looking to participate in Maths Olympiads and other forms of competition.
Exercise 2.2 outlines how to write and solve expressions with specific values. To help you understand clearly, the NCERT Solutions for Class 7 Maths Chapter 2 explain the solutions in a step-by-step manner. Click below to download PDF for free:
In Exercise 2.2 of Class 7 maths Chapter 2, you will learn to apply expressions to real problems. Some of the key concepts in this exercise are:
1. Find the values of the following expressions by writing the terms in each case.
(a) 28−7+8
(b) 39−2×6+11
(c) 40−10+10+10
(d) 48−10×2+16÷2
(e) 6×3−4×8×5
Sol. (a) 28−7+8=28+(−7)+8
Terms: 28,−7, and 8
28−7+8
=28+(−7)+8
=21+8=29
(b) 39−2×6+11=39+(−2×6)+11
Terms: 39,−2×6, and 11
39−2×6+11
=39+(−2×6)+11
=39+(−12)+11
=27+11
=38
(c) 40−10+10+10=40+(−10)+10+10
Terms: 40,−10,10, and 10
40−10+10+10
=40+(−10)+10+10
=30+10+10
=40+10
=50
(d) 48−10×2+16÷2=48+(−10×2)
+(16÷2)
Terms: 48,−10×2,16÷2
48−10×2+16÷2
=48+(−10×2)+(16÷2)
=48+(−20)+(8)
=28+8=36
(e) 6×3−4×8×5=(6×3)+(−4×8×5)
Terms: 6×3,4×8×5
6×3−4×8×5
=(6×3)+(−4×8×5)
=18+(−160)
=−142
2. Write a story/situation for each of the following expressions and find their values.
(a) 89+21−10
(b) 5×12−6
(c) 4×9+2×6
Sol. (a) 89+21−10
Story/Situation: Rahul had 89 stickers in his collection. His friend gifted him 21 more stickers for his birthday. Later, Rahul gave 10 of his stickers to his younger sister.
Value: 89+21−10=100.
(b) 5×12−6
Story/Situation: There are 5 boxes, and each box contains 12 pencils. 6 pencils were removed from the boxes to be given to a friend.
Value: 5×12−6=54.
(c) 4×9+2×6
Story/Situation: In a garden, there are 4 rows of flowerbeds, and each row has 9 plants. In another part of the garden, there are 2 rows of trees, and each row has 6 trees.
Value: 4×9+2×6=48.
3. For each of the following situations, write the expression describing the situation, identify its terms and find the value of the expression.
(a) Queen Alia gave 100 gold coins to Princess Elsa and 100 gold coins to Princess Anna last year. Princess Elsa used the coins to start a business and doubled her coins. Princess Anna bought jewellery and has only half of the coins left. Write an expression describing how many gold coins Princess Elsa and Princess Anna together have.
(b) A metro train ticket between two stations is ₹40 for an adult and ₹20 for a child. What is the total cost of tickets:
(i) for four adults and three children?
(ii) for two groups having three adults each?
(c) Find the total height of the window by writing an expression describing the relationship among the measurements shown in the picture.
Sol. (a) Number of gold coins Princess Elsa got = 100
Number of gold coins Princess Anna got = 100
Princess Elsa used the coins to start the business and doubled her coins. So, the number of coins Princess Elsa has =2×100
Princess Anna bought jewelry and has only half of the coins left.
So, the number of coins Princess Anna has =100/2
Therefore, the total number of gold coins Princess Elsa and Princess Anna have together =2×100+100/2
Thus, the expression describing the above situation is 2×100+100/2
Terms: 2×100,100/2
Now, 2×100+100/2=200+50
=250 gold coins
(b) (i) Metro train ticket for an gold coins adult
=₹40
So, the metro train ticket for four adults =4×40
Metro train ticket for a child= ₹ 20 So, the metro train ticket for three children =3×20
Therefore, the expression describing the total cost of tickets for four adults and three children is 4×40+3×20
Terms: 4×40,3×20
Now, 4×40+3×20=160+60
= ₹220
(ii) Metro train ticket for an adult =₹40
So, the metro train ticket for a group of three adults =3×40
Therefore, the expression describing the total cost of tickets for the two groups having three adults each is 2×(3×40).
Terms: 2×(3×40)
Now, 2×(3×40)=2×120=₹240
(c) By observing the given picture,
the total height of the window = number of gaps ×5 cm+ number of grills ×2 cm+ number of borders ×3 cm=7×5+6×2+2×3
Terms: 7×5,6×2,2×3
Now, 7×5+6×2+2×3
=35+12+6=47+6=53 cm
(Session 2026 - 27)