NCERT Solutions Class 7 Maths Chapter 6 Number Play Exercise 6.2

Exercise 6.2 of Class 7 Maths Chapter 6  Number Play is all about finding interesting patterns in numbers. In this exercise, you will discover how to make magic squares from a variety of numbers. This is a meaningful way to understand relationships between numbers, as well as building up your skills with addition and logic.

This topic is invaluable in developing a better ability to solve problems. Doing these questions is going to help you tremendously when studying for your school exams as well as building confidence, particularly with question papers involving a lot of logical puzzles.

All of the questions in this exercise are based on the latest NCERT syllabus for Class 7 Maths. The NCERT Solutions we provide are comprehensive and clearly explain all the steps that you need to take to solve your exercise correctly. You can also use these solutions on revision, and develop a strong base for Maths skills in the future.

1.0Download NCERT Solutions Class 7 Maths Chapter 6 Number Play Exercise 6.2: Free PDF

Exercise 6.2 focuses on magic squares when solving and creating them with simple number tricks. These NCERT Solutions for Class 7 Maths Chapter 6 provide easy and clear answers and explanations for each question. You can download the free PDF from below:

2.0Key Concepts in Exercise 6.2 of Class 7 Maths Chapter 6

Exercise 6.2 teaches you how numbers can be arranged in unique ways.
Here are the key concepts you will learn:

• Magic squares and how they work
• Finding missing numbers in a magic square
• Understanding equal sums in rows, columns, and diagonals
• Using logic to complete number patterns
• Improving addition and pattern recognition skills

3.0NCERT Solutions Class 7 Maths Chapter 6 Number Play : Other Exercises

4.0Detailed Solutions for Class 7 Maths Chapter 6 Exercise 6.2

1. Using your understanding of the pictorial representation of odd and even numbers, find out the parity of the following sums:

(a) Sum of 2 even numbers and 2 odd numbers (e.g., even + even + odd + odd)

(b) Sum of 2 odd numbers and 3 even numbers

(c) Sum of 5 even numbers

(d) Sum of 8 odd numbers

Sol. (a) Even + Even = Even and Odd + Odd = Even

Adding the two results, we get

Even + Even = Even .

The parity of the result is even.

Example:

4+6+3+5=10+8=18 (Even)

(b) Odd + Odd = Even

and Even + Even + Even = Even

Adding the two results, we get

Even + Even = Even

The parity of the result is even.

Example:

5+7+4+6+8=12+18=30 (Even)

(c) Adding any 5 even numbers always gives an even number.

The parity of the result is even.

Example: 2+4+6+8+10=30 (Even)

(d) Odd + Odd = Even (4 such pairs).

Adding the 4 such results, we get

Even + Even + Even + Even = Even

The parity of the result is even.

Example: 1+3+5+7+9+11+13+15=64 (Even)

2. Lakpa has an odd number of ₹1 coins, an odd number of ₹5 coins and an even number of ₹10 coins in his piggy bank. He calculated the total and got ₹205. Did he make a mistake? If he did, explain why. If he didn't, how many coins of each type could he have?

Sol. Lakpa has an odd number of ₹ 1 coins, so, their total value is odd.

He also has an odd number of ₹ 5 coins, so their total is also odd.

The ₹ 10 coins are even in numbers, so their total is even.

Now, adding two odd sums, we get

Odd (from ₹ 1) + Odd (from ₹ 5) = Even

Adding the ₹ 10 coins' total (even sum) to this even sum,

Even + Even = Even

3. Since 205 is an odd number, the total of ₹ 205 is not possible with an odd number of ₹ 1 and ₹ 5 coins and an even number of ₹ 10 coins. Therefore, Lakpa made a mistake in his calculation.

We know that:

(a) even + even = even

(b) odd + odd = even

(c) even + odd = odd

Similarly, find out the parity for the scenarios below:

(d) even - even = ____

(e) odd - odd = ____

(f) even - odd = ____

(g) odd - even = ____

Sol. (d) even - even = ____

8−4=4→ even

10−4=6→ even

Parity of result = even

∴ even - even = even

(e) odd - odd = ____

5−3=2→ even

9−3=6→ even

Parity of result = even

∴ odd - odd = even

(f) even - odd = ____

6−3=3

10−5=5

Parity of result = odd

∴ even - odd = odd

(g) odd - even = ____

5−2=3

11−6=5

Parity of result = odd

∴ odd - even = odd

5.0Key Features and Benefits of Class 7 Maths Chapter 6 Exercise 6.2

• These solutions are from the revised NCERT maths syllabus for Class 7.
• They introduce magic squares to kids in a fun and simple way.
• Students can improve their logical reasoning and number skills by practicing these solutions.
• This also prepares students for the CBSE exams with pattern-based questions.
• They help to develop a good foundation to solve olympiad-level problems.
• The NCERT solutions provide answers in a step by step method for easy understanding and practice with confidence.