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NCERT Solutions
Class 8
Maths
Chapter 4 Quadrilaterals
Exercise 4.1

NCERT Class 8 Maths Ch. 4 Quadrilaterals Other Exercises:-

Exercise 4.1


NCERT Solutions Class 8 Maths All Chapters:-

Chapter 1 - A Square and a Cube

Chapter 2 - Power play

Chapter 3 - A story of Numbers

Chapter 4 - Quadrilaterals

Chapter 5 - Number Play

Chapter 6 - We distibute, yet thinmgs multiply

Chapter 7 - Proportional Reasoning

Frequently Asked Questions

A simple curve is a drawing that does not cross over itself at any point. If the line crosses itself (like the number 8), it is not a simple curve.

No. A polygon must be made up entirely of straight line segments. Since a circle is a curved line, it does not qualify as a polygon.

For a polygon to be regular, it must satisfy two conditions: all of its sides must be the same length, and all of its interior angles must be equal. An equilateral triangle and a square are examples of regular polygons.

No. A diagonal connects two non-consecutive vertices. In a triangle, every vertex is connected to the others by sides, so there are no non-consecutive vertices to connect.

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NCERT Solutions for Class 8 Maths Chapter 4 Quadrilaterals - Exercise 4.1

Mastering the classification of polygons and curves is simple with our NCERT Solutions for Class 8 Maths Ch 4: Understanding Quadrilaterals – Exercise 4.1. In this chapter, we explore the world of plane figures, distinguishing between open and closed curves, and identifying the unique properties of various polygons.

Class 8 Math Lessons (Ch 4): Learn to Classify Shapes with Ease! The solutions to Exercise 4.1 will be presented in a step-by-step approach to give students a clear understanding of concave vs. convex polygons and the angle sum property. These solutions are in accordance with the CBSE Guidelines to provide the best path for improving accuracy in geometry. Additionally, these solutions build the foundation needed for more complex constructions and proofs in later exercises.

1.0Download Class 8 Maths Chapter 4 Ex 4.1 NCERT Solutions PDF

You can get our simple NCERT Solutions for Class 8 Maths Chapter 4 Exercise 4.1 in PDF format. Ideal for rapid reference and offline study.

NCERT Solutions Class 8 Maths Chapter 4 Ex 4.1

Download PDF

2.0Detailed NCERT Class 8 Maths Chapter 4 Solutions of Exercise 4.1

1.Find all the other angles inside the following rectangles.

Sol. (i) The given rectangle is ABCD . D C

We have ∠1=30∘ ∠1+∠2=90∘ ∴∠2=90∘−∠1=90∘−30∘=60∘ MD=MA ⇒∠3=∠2=60∘ ∠3+∠Z4=90∘ ∴∠4=90∘−∠3=90∘−60∘=30∘ MC=MD ⇒∠5=∠4=30∘ ∠5+∠6=90∘ ∴∠6=90∘−∠5=90∘−30∘=60∘ MB=MC ⇒∠7=∠6=60∘ MB=MA ∠8=∠1=30∘ In △AMB, we have ∠1+∠9+∠8=180∘ ∴30∘+∠9+30∘=180∘ ∴∠9+180∘−60∘=120∘ ∠11=∠9=120∘ (Vertically opposite angles) ∠9+∠10=180∘ (Linear angles) ∴∠10=180∘−120∘=60∘ ∠12=∠10=60∘ (Vertically opposite angles) ∴∠2=60∘,∠3=60∘,∠4=30∘, ∠5=30∘,∠6=60∘,∠7=60∘, ∠8=30∘,∠9=120∘,∠10=60∘, ∠11=120∘, and ∠12=60∘, (ii) The given rectangle is PSRQ.

Q R

We have ∠9=110∘ ∠11+∠9=110∘ (Vertically opposite angles) ∠9+∠10=180∘ (Linear angles) ∴∠10=180∘−110∘=70∘ ∠12=∠10=70∘ (Vertically opposite angles) MP=MS ⇒∠1=∠8 In △PMS, we have ∠1+∠11+∠8=180∘ ⇒∠1+110∘+∠1=180∘ ⇒2∠1=180∘−110∘ ⇒2∠1=70∘ ⇒∠1=35∘ ∴∠8 is also 35∘. ∴∠1+∠2=90∘ ⇒∠2=90∘−∠1 ⇒∠2=90∘−35∘ ⇒∠2=55∘ MQ=MP ⇒∠3=∠2=55∘ ∴∠3+∠4=90∘ ⇒∠4=90∘−∠3 ⇒∠4=90∘−55∘ ⇒∠4=35∘ MR=MQ ⇒∠5=∠4=35∘ ∴∠5+∠6=90∘ ⇒∠6=90∘−∠5 ⇒∠6=90∘−35∘ ⇒∠6=55∘ MS=MR ⇒∠7=∠6=55∘ ∴∠1=35∘,∠2=55∘,∠3=55∘, ∠4=35∘,∠5=35∘,∠6=55∘,∠7=55∘, ∠8=35∘,∠10=70∘,∠11=110∘ and ∠12=70∘. 2. Draw a quadrilateral whose diagonals have equal lengths of 8 cm that bisect each other, and intersect at an angle of (i) 30∘ (ii) 40∘ (iii) 90∘ (iv) 140∘

Sol. (i) Draw a line AB equal to 8 cm . Take point M on AB such that AM=BM=4 cm. Using a protractor, draw an angle of 30∘ at M on MB . On this line, take points C and D such that MC=MD=4 cm. Join AD,DB,BC, and CA . ABCD is the required quadrilateral.

Since diagonals AB and CD are equal and are bisecting each other at M, ACBD is a rectangle. (ii) Draw a line AB equal to 8 cm . Take point M on AB such that AM=BM=4 cm.

Using a protractor, draw an angle of 40∘ at M on MB . On this line, take points C and D such that MC=MD=4 cm. Join AD,DB,BC, and CA.ABCD is the required quadrilateral.

Since diagonals AB and CD are equal and are bisecting each other at M , ACBD is a rectangle. (iii) Draw a line AB equal to 8 cm . Take a point M on AB such that AM=BM=4 cm. Using a protractor, draw an angle of 90∘ at M on MB . On this line, take points C and D such that MC=MD=4 cm. Join AD,DB,BC, and CA.ACBD is the required square.

Since diagonals AB and CD are equal and are bisecting each other at M , and also the diagonals are perpendicular to each other, ACBD is a square. (iv) Draw a line AB equal to 8 cm . Take a point M on AB such that AM=BM= 4 cm .

Using a protractor, draw an angle of 140∘ at M on MB.

On this line, take points C and D such that MC=MD=4 cm.

Join AD,DB,BC, and CA.ACBD is the required quadrilateral.

Since diagonals AB and CD are equal and are bisecting each other at M , ACBD is a rectangle. 3. Consider a circle with centre O . Line segments PL and AM are two perpendicular diameters of the circle. What is the figure APML? Reason and/or experiment to figure this out. Sol. In the figure, PL and AM are two perpendicular diameters of the circle. Let r be the radius of the circle.

Since PL=PO+OL=r+r=2r and AM=AO+OM=r+r=2r ∴PL=AM ∴ In the quadrilateral APML, diagonals PL and AM are equal and are perpendicular to each other.

Also, OP=OA=OL=OM=r ∴ Diameters PL and AM bisect each other at 0 . ∴ Quadrilateral APML is a square. 4. We have seen how to get 90∘ using paper folding. Now, suppose we do not have any paper but two sticks of equal length, and a thread. How do we make an exact 90∘ using these?

Sol. Let AB and CD be two sticks of equal length, say 6 cm .

Mark the midpoints of the sticks using a ruler.

Fix a screw to the sticks at their midpoints. Using a thread, measure distances AD and BD .

Keep on moving the sticks about the screw, so that the distances AD and BD are equal.

In this position, fix the sticks by tightening the screw.

The new positions of the sticks are shown in the figure.

Tie pieces of thread along AD and BD .

Consider △AMD and △BMD. We have AM=BM,AD=BD and MD is common. ∴ By the SSS condition, ΔAMD and ΔBMD are congruent. ∴∠AMD=∠BMD Also ∠AMD+∠BMD=180∘ (Linear angles) ∴∠AMD+∠AMD=180∘ ⇒2∠AMD=180∘ ⇒∠AMD=90∘ ∴∠AMD=∠BMD=90∘ ∴ Angle between the sticks is 90∘. 5. We saw that one of the properties of a rectangle is that its opposite sides are parallel. Can this be chosen as a definition of a rectangle? In other words, is every quadrilateral that has opposite sides parallel and equal, a rectangle?

Sol. Let ABCD be a quadrilateral in which opposite sides are parallel and equal. Here AB∥DC and AD∥BC. Also, AB=DC and AD=BC.

In the quadrilateral ABCD , opposite sides are equal.

For ABCD to be a rectangle, we require each angle to be 90∘.

Given information AB∥DC and AD∥BC can not help us to prove that each angle of ABCD is 90∘.

∴ABCD may not be a rectangle. ∴ A rectangle can not be defined as a quadrilateral with equal and parallel opposite sides.

3.0

Multiple choice questions

1.Which of the following is not true? (1) A plane figure formed by joining a number of points without lifting a pencil from the paper and without retracing any portion of the drawing other than single point is called a curve. (2) A simple closed curve made up of only line segments is called a polygon. (3)

is a figure of closed curve (4) None of these

2. A closed figure having three sides is (1) Not a polygon (2) A triangle (3) A quadrilateral (4) None of these

3. A heptagon is a (1) Polygon having 5 sides (2) Polygon having 6 sides (3) Both (1) and (2) (4) None of these

4. Adjacent sides of a polygon are (1) Any two sides of the polygon (2) Any two sides connecting two nonconsecutive vertices of a polygon (3) Any two sides with a common vertex (4) None of these

5. Adjacent vertices are (1) Uncommon vertices of two adjacent sides of a polygon (2) The end points of the same side of a polygon (3) The end points of the diagonal of a polygon (4) None of these

6. Which of the following is not true? (1) A quadrilateral in which one pair of opposite sides is parallel is called a trapezium. (2) A parallelogram has four sides. (3) A quadrilateral in which both the pairs of opposite sides are parallel is called a parallelogram. (4) The sum of all the four angles of a parallelogram is not 360∘.

7. Which of the following is not true? (1) Every trapezium is a parallelogram but every parallelogram is not a trapezium. (2) Opposite sides of a parallelogram are not equal. (3) Opposite angles of a parallelogram are equal. (4) Both (1) and (2)

8. Which of the following is not true? (1) A parallelogram having a pair of adjacent sides equal, is called a rhombus (2) The diagonals of a rhombus do not bisect each other (3) If the diagonals of a parallelogram bisect each other at right angles, it is a rhombus (4) A rectangle is a parallelogram.

9. In the figure, PQRS is a parallelogram. If ∠P=75∘, then ∠Q=

(1) 75∘ (2) 90∘ (3) 105∘ (4) 100∘

10. In the given figure, PQRS is a parallelogram. If perimeter of parallelogram PQRS is 40 cm and PQ=12 cm then PS is equal to

(1) 12 cm (2) 10 cm (3) 8 cm (4) 9 cm

11. In the given figure, PQRS is a parallelogram and diagonal PR and QS intersect each other at A . If QA=3 cm, AR=5 cm and PS=6 cm, then perimeter of △AQR is

(1) 16 cm (2) 14 cm (3) 12 cm (4) 10 cm

12. In the given figure, ABCD is a parallelogram, diagonals BD and AC intersect each other at E . If BE+CE=8 cm, then AC+BD is equal to

(1) 16 cm (2) 14 cm (3) 20 cm (4) 24 cm

13. Which of the following is not the property of a rectangle? (1) A rectangle is a parallelogram in which one of the angles is a right angle. (2) Diagonals of a rectangle are equal (3) Opposite sides of a rectangle are equal (4) Diagonals of a rectangle bisect each other at right angle

14. In the given figure, ABCD is a rhombus. Diagonals AC and BD intersect each other at E . If ∠1=50∘ then ∠BCD=

(1) 100∘ (2) 90∘ (3) 80∘ (4) None of these

15. Which one has all the properties of a parallelogram and also that of a kite? (1) Trapezium (2) Rhombus (3) Rectangle (4) None of these

16. In a parallelogram if each angle is equal, then it is called (1) Rectangle (2) Square (3) Rhombus (4) None of these

17. Which of these is not necessarily a property of a rhombus? (1) All sides are equal (2) Opposite angles are equal (3) Diagonals are equal (4) Diagonals bisect each other at right angles

18. A square is a special case of which of the following? (1) Parallelogram (2) Rectangle (3) Rhombus (4) All of these

19. Statement 1: In a parallelogram, the adjacent angles are in the ratio 2:3, so the bigger angle of the parallelogram is 108∘.

Statement 2: The sum of adjacent angles of a parallelogram is equal to 180∘. (1) Statement-1 is true and Statement-2 is false. (2) Statement-1 is false and Statement-2 is true. (3) Both the statements are true. (4) Both the statements are false.

20. Statement-1: In a kite, the diagonals are equal.

Statement-2: In a kite, the diagonals intersect at right angles. (1) Statement-1 is true and Statement-2 is false. (2) Statement-1 is false and Statement-2 is true. (3) Both the statements are true. (4) Both the statements are false.

True or false

21.The opposite sides of a rectangle are equal.

22. The diagonals of a rectangle are equal.

23. The diagonals of a rectangle are perpendicular to each other.

24. The diagonals of a rectangle bisect each other.

25. The diagonals of a rectangle bisect each other at right angles.

26. The diagonals of a rectangle are equal and bisect each other.

27. If the diagonals of a quadrilateral are perpendicular to each other, it is always a square.

28. If the diagonals of a rhombus are equal it is always a square.

29. The diagonals of a parallelogram are equal and bisect each other.

Crossword puzzle: 30.

Across

b. A parallelogram with four congruent sides. e. Any 4-sided polygon. f. A parallelogram with opposite congruent sides and four right angles. g. A quadrilateral with two distinct pairs of equal adjacent sides.

Down

a. A quadrilateral with exactly one pair of parallel sides. c. A quadrilateral whose opposite sides are parallel and congruent and opposite angles are congruent. d. A parallelogram with four congruent sides and four congruent angles.

ANSWER KEY

Multiple choice questions

Question123456789101112131415
Answer424324423321432
Question1617181920
Answer13432

True or false 21. True 22. True 23. False 24. True 25. False 26. True 27. False 28. True 29. False

Crossword puzzle 30.

4.0

5.0Key Concepts of Chapter 4 Exercise 4.1

  • Classification of Curves: Identifying simple closed curves, simple curves that are not closed, and figures that are not simple curves.
  • Polygons: A simple closed curve made up of only line segments.
  • Convex and Concave Polygons:
  • Convex: All diagonals lie inside the polygon; no interior angle is greater than 180°.
  • Concave: At least one diagonal lies outside the polygon; at least one interior angle is greater than 180°.
  • Regular and Irregular Polygons: A regular polygon is both equiangular (all angles equal) and equilateral (all sides equal).
  • Angle Sum Property: The sum of the interior angles of a polygon with n sides is given by the formula (n−2)×180∘.

6.0NCERT Solutions for Class 8 Maths Chapter 4 Quadrilaterals : All Exercises

NCERT Solutions for Class 8 Maths Chapter 4 Quadrilaterals - Exercise 4.1

7.0Benefits of NCERT Solutions for Class 8 Maths Chapter 4 Exercise 4.1

  • Conceptual Clarity: Clearly distinguishes between curves and polygons using visual logic.
  • Formula Mastery: Provides repetitive practice for the diagonal and angle sum formulas.
  • Logical Steps: Shows exactly how to identify if a shape is regular or irregular.
  • Error Prevention: Teaches students to check for "caved-in" angles to identify concave polygons quickly.