Lewis dot structures are a fundamental concept in Chemistry, vital for understanding how atoms bond and interact. Named after Gilbert N. Lewis, these diagrams visually represent the valence electrons of an atom, which are the electrons participating in chemical bonding. For JEE aspirants, mastering Lewis structures is crucial as it forms the basis for advanced topics such as molecular geometry, resonance, and hybridization.
Bromine is a chemical element with the symbol Br and atomic number 35. It is a halogen, found in Group 17 of the periodic table. In its elemental form, bromine is a reddish-brown liquid at room temperature, known for its distinct color and strong odor. Understanding the electronic configuration and valence electrons of bromine is essential for drawing its Lewis dot structure.
Bromine, like other halogens, is highly reactive and tends to form negative ions (anions) by gaining one electron.
Valence electrons are the electrons present in the outermost shell of an atom. They determine the atom’s chemical properties and its ability to bond with other atoms.
Bromine’s Valence Electrons: The electronic configuration of bromine ends with 4s2 4p5.
Total valence electrons = 2 (4s) + 5 (4p) = 7 valence electrons
Knowing the number of valence electrons is the first step in drawing a Lewis dot structure.
The Lewis dot structure of bromine represents its symbol (Br) surrounded by dots, each dot signifying a valence electron. Since bromine has 7 valence electrons, we place seven dots around the symbol.
Visual Representation:
Or, in a more linear text format: Br with 7 single dots placed around it (one pair on three sides, one single on the fourth).
Drawing the Lewis structure of bromine is essential for understanding its bonding behavior and reactivity. Follow these steps:
Determine the Number of Valence Electrons
Represent the Atoms
Distribute the Electrons
Final Lewis Structure
The Lewis structure for Br₂ is:
Each colon (:) represents a lone pair of electrons, and the dash (—) represents a shared pair of electrons forming a single bond
The unpaired electron in bromine’s Lewis structure indicates its tendency to form a single covalent bond, typically with another halogen or hydrogen atom (as in HBr). This is because halogens need just one more electron to achieve a stable octet configuration (8 electrons in their outer shell).
Each bromine atom shares its single unpaired electron, forming a single covalent bond:
Understanding the Lewis dot structure of bromine has several applications:
Molecular geometry refers to the three-dimensional arrangement of atoms in a molecule. For the bromine molecule (Br2), the geometry is straightforward. Since it consists of only two atoms, the geometry is linear. The two atoms are connected by a single bond, resulting in a straight line.
In the Br2 molecule, each bromine atom undergoes sp3 hybridisation. The ground state electronic configuration of a bromine atom is 4s24p5. In the hybridized state, one s and three p orbitals mix to form four equivalent sp3 hybrid orbitals. One of these orbitals contains the single unpaired electron and overlaps with a similar orbital from the other bromine atom to form the σ bond. The other three sp3 hybrid orbitals contain the three lone pairs of electrons. The sp3 hybridization gives the electron pairs a tetrahedral arrangement around each atom, but the molecular geometry is linear due to the two-atom structure.
The bromine molecule (Br2) is nonpolar. This is because the bond is between two identical atoms. Since the electronegativity of the two bromine atoms is the same, there is no difference in charge distribution. The shared electrons are equally attracted to both nuclei, resulting in a symmetrical molecule with no net dipole moment.
(Session 2026 - 27)