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NCERT Solutions
Class 6
Maths
Chapter 7 Fractions
Exercise 7.6

NCERT Solutions Class 6 Maths Chapter 7 fractions Exercise 7.6

Exercise 7.6 from NCERT Class 6 Maths Chapter 7 – Fractions helps students to use their knowledge of the topic in real-life situations. This exercise consists of a combination of word problems that require students to add and subtract both like and unlike fractions. Students learn to understand how fractional calculations are used in day-to-day life; sharing food, splitting money, measuring lengths, etc.

ALLEN’s NCERT Solutions Class 6 Maths for Exercise 7.6 on Fractions give importance to the application-based problem-solving abilities of students. Entry-level solutions are effectively designed to help students understand how to interpret word problems, internalize some of the reasoning behind these problems, and solve the problems correctly and with confidence in a new context. These solutions directly align with the latest NCERT curriculum!

1.0Download NCERT Solutions Class 6 Maths Chapter 7 fractions Exercise 7.6: Free PDF

Download our NCERT Solutions Class 6 Maths Chapter 7 Exercise 7.6 PDF for free. It includes fully solved, easy-to-understand word problems curated by ALLEN experts—perfect for quick revision and homework support.

NCERT Solutions for Class 6 Maths Chapter 7 - Exercise 7.6

2.0NCERT Solutions Class 6 Chapter 7 Fractions: All Exercises

NCERT Solutions Class 6 Maths Chapter 7 Exercise 7.1

NCERT Solutions Class 6 Maths Chapter 7 Exercise 7.2

NCERT Solutions Class 6 Maths Chapter 7 Exercise 7.3

NCERT Solutions Class 6 Maths Chapter 7 Exercise 7.4

NCERT Solutions Class 6 Maths Chapter 7 Exercise 7.5

NCERT Solutions Class 6 Maths Chapter 7 Exercise 7.6

NCERT Solutions Class 6 Maths Chapter 7 Exercise 7.7

NCERT Solutions Class 6 Maths Chapter 7 Exercise 7.8

3.0NCERT Class 6 Maths Chapter 7 fractions Exercise 7.6: Detailed Solutions

  • Are 63​,84​,105​ equivalent fractions? Why? Sol. Since, 63​⇒6÷33÷3​=21​ 84​⇒8÷44÷4​=21​ and 105​⇒10÷55÷5​=21​ Since three fractions have same value when simplified, so they are equivalent fractions.
  • Write two equivalent fractions for 32​. Sol. 62​⇒6×22×2​=124​ ⇒6×32×3​=186​
  • 64​=□=□=□=.................(write as many you can) 64​=128​=1812​=2416​= Sol. 64​⇒6×24×2​=128​;6×34×3​=1812​;6×44×4​=2416​; 64​=128​=1812​=2416​=
  • Three rotis are shared equally by four children. Show the division in the picture and write a fraction for how much each child gets. Also, write the corresponding division facts, addition facts, and, multiplication facts. Fraction of roti each child gets is . Division fact: Addition fact: Multiplication fact: Compare your picture and answers
    with your classmates! Sol.
    Division fact ⇒3 wholes divided in 4 parts =3÷4=43​ Addition fact ⇒ Four times 43​ added gives 3 wholes =43​+43​+43​+43​=412​=3 Multiplication fact ⇒4 parts of 43​ make 3 wholes =4×43​=3
  • Draw a picture to show how much each child gets when 2 rotis are shared equally by 4 children. Also, write the corresponding division facts, addition facts, and multiplication facts. Sol. As 2 rotis have to be shared equally by 4 children we divide each roti in 4 parts and give
    (a) 1 part of each roti to each-child as shown below :
    (b) 2 parts to each child as shown below :
    Division fact ⇒2 whole divides in 4 parts 2÷4 or 42​=21​ Addition fact ⇒42​+42​+42​+42​=48​=2 Multiplication fact =4×42​=2
  • Anil was in a group where 2 cakes were divided equally among 5 children. How much cake would Anil get? Sol.
    Each cake gets divided into 5 parts and Anil gets one part from each cake i.e. 51​+51​=52​.
  • Find the missing numbers: (a) 5 glasses of juice shared equally among 4 friends is the same as glasses of juice shared equally among 8 friends. So, 45​=8□​ □ (b) 4 kg of potatoes divided equally in 3 bags is the same as 12 kgs of potatoes divided equally in __ bags. So, 34​=□12​ □ (c) 7 rotis divided among 5 children is the same as rotis divided among children. So, 57​=□□​. □ Sol. (a) 45​=8□​ □ Since 4×2=8 So, 5×2=10 ⇒45​=810​ (b) 34​=□12​ Since 4×3=12 So, 3×3=9 34​=912​ (c) 57​=□□​ □ 7×2=14;7×3=21;7×4=28 5×2=10;5×3=15;5×4=20 57​=1014​;57​=1521​;57​=1028​
  • Find equivalent fractions for the given pairs of fractions such that the fractional units are the same. (a) 27​ and 53​ (b) 38​ and 65​ (c) 43​ and 53​ (d) 76​ and 58​ (e) 49​ and 25​ (f) 101​ and 92​ (g) 38​ and 411​ (h) 613​ and 91​ Sol. (a) The smallest common multiple of 2 and 5 is 10. 2×57×5​=1035​;5×23×2​=106​ (b) The smallest common multiple of 3 and 6 is 6 . 3×28×2​=616​=6×15×1​=65​ (c) The smallest common multiple of 4 and 5 is 20 . 4×53×5​=2015​;5×43×4​=2012​ (d) The smallest common multiple of 7 and 5 is 35 . 7×56×5​=3530​;5×78×7​=3542​ (e) The smallest common multiple of 4 and 2 is 4 . 4×19×1​=49​=2×25×2​=410​ (f) The smallest common multiple of 10 and 9 is 90 . 10×91×9​=909​;9×102×10​=9020​ (i) The smallest common multiple of 3 and 4 is 12 . 3×48×4​=1232​=4×311×3​=1233​ (h) The smallest common multiple of 6 and 9 is 18. 6×313×3​=1839​;9×21×2​=182​
  • Express the following fractions in lowest terms: (a) 5117​ (b) 14464​ (c) 147126​ (d) 112525​ Sol. (a) Since, 17 is common factor of 17 and 51, So, 51÷1717÷17​=31​ (b) 14464​⇒144÷264÷2​=7232​⇒72÷232÷2​=3616​ ⇒36÷216÷2​=188​⇒18÷28÷2​=94​ (c) Since 3 is common factor of 126 and 147, 147÷3126÷3​=4942​⇒49÷742÷7​=76​ (d) Since 7 as common multiple of 525 and 112, 112÷7525÷7​=1675​

4.0Key Features and benefits for Class 6 Maths Chapter 7 Exercise 7.6

Clear Step-by-Step Format: Complex word problems are broken down into simple steps with explanations.

Latest NCERT & CBSE 2025–26 Syllabus: Fully updated to reflect the latest academic guidelines.

Perfect for Exam Preparation: Builds problem-solving confidence and supports scoring high in school assessments.

Improves Logical Thinking: Encourages critical thinking through story-based numerical problems.

Homework & Revision Friendly: Ideal for daily schoolwork, practice sheets, and pre-exam revision.

Created by ALLEN Experts: Designed by India’s top Maths educators and reviewed for accuracy and clarity.

NCERT Class 6 Maths Ch. 7 Fractions Other Exercises:-

Exercise 7.1

Exercise 7.2

Exercise 7.3

Exercise 7.4

Exercise 7.5

Exercise 7.6

Exercise 7.7

Exercise 7.8

NCERT Solutions for Class 6 Maths Other Chapters:-

Chapter 1: Patterns in Mathematics

Chapter 2: Lines and Angles

Chapter 3: Number Play

Chapter 4: Data Handling and Presentation

Chapter 5: Prime Time

Chapter 6: Perimeter and Area

Chapter 7: Fractions

Chapter 8: Playing With Construction

Chapter 9: Symmetry

Chapter 10: The Other Side of Zero

Frequently Asked Questions

Exercise 7.6 concentrates on the addition and subtraction of unlike fractions, requiring the crucial step of finding a common denominator.

The solutions provide detailed guidance on finding the Least Common Multiple (LCM) of denominators to convert unlike fractions into equivalent like fractions before performing addition or subtraction.

Many solutions for Exercise 7.6 include examples that illustrate how to handle the addition and subtraction of multiple unlike fractions, often involving mixed numbers as well.

Finding the LCM, as emphasized in Exercise 7.6, is essential because it allows fractions with different denominators to be transformed into equivalent fractions with a common base, enabling direct addition or subtraction of their numerators.

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