NCERT Solutions Class 6 Maths Chapter 7 fractions Exercise 7.7

Exercise 7.7 of NCERT Class 6 Maths Chapter 7 - Fractions is now complete and marks the final opportunity for students to revise and display all the skills they have acquired in this chapter. This exercise contains a variety of types of problems, which include elements of identifying, comparing, adding, subtracting, and simplifying fractions as well as the student’s overall understanding of how to apply what they have learned in different formats.

ALLENS NCERT Solutions Class 6 Maths, Exercise 7.7 have been created to empower students to revise easily, whether this means completing mixed-type problems are refreshing their core skills used to complete these types of problems, through the step-by-step examples we assist students work through every question clearly helping them feel ready for their Exams or assessment.

1.0Download NCERT Solutions Class 6 Maths Chapter 7 fractions Exercise 7.7: Free PDF

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2.0NCERT Solutions Class 6 Chapter 7 Fractions: All Exercises

3.0NCERT Class 6 Maths Chapter 7 fractions Exercise 7.7: Detailed Solutions

• Compare the following fractions and justify your answers: (a) $\frac{8}{3},\frac{5}{2}$ (b) $\frac{4}{9},\frac{3}{7}$ (c) $\frac{7}{10},\frac{9}{14}$ (d) $\frac{12}{5},\frac{8}{5}$ (e) $\frac{9}{4},\frac{5}{2}$ Sol. (a) The smallest common multiple of 3 and $2,4,6$. $\frac{8\times 2}{3\times 2}=\frac{16}{6};\frac{5\times 3}{2\times 3}=\frac{15}{6}$ Since $\frac{16}{6}>\frac{15}{6}$ $\frac{8}{3}>\frac{5}{2}$ (b) The smallest common multiple of 9, 7 is 63. $\frac{4}{9}\times \frac{7}{7}=\frac{28}{63};\frac{3}{7}\times \frac{9}{9}=\frac{27}{63}$ $\because \frac{28}{63}>\frac{27}{63}$ Now $\frac{4}{9}>\frac{3}{7}$ (c) The smallest common multiple of 10,14 , is 70 . $\frac{7\times 7}{10\times 7}=\frac{49}{70};\frac{9}{14}\times \frac{5}{5}=\frac{45}{70}$ $\because \frac{49}{70}>\frac{45}{70}$ $\Rightarrow \frac{7}{10}>\frac{9}{14}$ (d) $\because$ Both fraction have same denominators, $\frac{12}{5}>\frac{8}{5}$ (e) The smallest common multiple of 4, 2 is 4 . $\frac{9}{4}\times \frac{1}{2}=\frac{9}{4};\frac{5\times 2}{2\times 2}=\frac{10}{4}$ $\because \frac{9}{4}<\frac{10}{4}$ $\Rightarrow \frac{9}{4}<\frac{5}{2}$.
• Write the following fractions in ascending order. (a) $\frac{7}{10},\frac{11}{15},\frac{2}{5}$ (b) $\frac{19}{24},\frac{5}{6},\frac{7}{12}$ Sol. (a) The smallest common multiple of $10,15,5$, is 30 . $\begin{array}{ll}& \frac{7\times 3}{10\times 3}=\frac{21}{30};\frac{11\times 2}{15\times 2}=\frac{22}{30};\frac{2\times 4}{5\times 6}=\frac{12}{30}\\ \because & \frac{12}{30}<\frac{21}{30}<\frac{22}{30}\\ \Rightarrow & \frac{2}{5}<\frac{7}{10}<\frac{11}{15}\text{ (ascending order) }\end{array}$ (b) The smallest common multiple of $24,6,12$, is 24 . $\begin{array}{rl}& \frac{19\times 1}{24\times 1}=\frac{19}{24};\frac{5\times 4}{6\times 4}=\frac{20}{24};\frac{7\times 2}{12\times 2}=\frac{14}{24}\\ \Rightarrow & \frac{7}{12}<\frac{19}{24}<\frac{5}{6}\text{ (ascending order) }\end{array}$
• Write the following fractions in descending order. (a) $\frac{25}{16},\frac{7}{8},\frac{13}{4},\frac{17}{32}$ (b) $\frac{3}{4},\frac{12}{5},\frac{7}{12},\frac{5}{4}$ Sol. (a) The smallest common multiple of $16,8,9,32$ is 32 $\begin{array}{rl}& \frac{25\times 2}{16\times 2}=\frac{50}{32};\frac{7\times 4}{8\times 4}=\frac{28}{32};\frac{13\times 8}{4\times 8}=\frac{104}{32};\frac{17\times 1}{32\times 1}=\frac{17}{32}\\ & \because \frac{104}{32}>\frac{50}{32}>\frac{28}{32}>\frac{17}{32}\\ & \Rightarrow \frac{13}{4}>\frac{25}{16}>\frac{7}{8}>\frac{17}{32}\text{ (descending order) }\end{array}$ (b) The smallest common multiple of $4,5,12$, is 60 . $\frac{3\times 15}{4\times 15}=\frac{45}{60};\frac{12\times 12}{5\times 12}=\frac{144}{60};\frac{7\times 5}{12\times 5}=\frac{35}{60};\frac{5\times 15}{4\times 15}=\frac{75}{60}$ $\because \frac{144}{60}>\frac{75}{60}>\frac{45}{60}>\frac{35}{60}$ $\Rightarrow \frac{12}{5}>\frac{5}{4}>\frac{3}{4}>\frac{7}{12}$ (descending order)

4.0Key Features and benefits for Class 6 Maths Chapter 7 Exercise 7.7

Complete Problem-Solving: Our NCERT Solutions offer detailed answers and explanations for every word problem in Exercise 7.7, ensuring no concept is overlooked.

Step-by-Step Approach: Each solution is presented in an easy-to-follow, step-by-step format, simplifying even the most challenging application-based questions.

Accuracy and Reliability: Developed by experienced educators, these solutions are highly accurate and strictly adhere to the latest NCERT syllabus guidelines for 2025-2026.

Enhanced Conceptual Understanding: Beyond just providing answers, our solutions aim to build a strong conceptual foundation in applying fractions to real-life situations.

Efficient Study Aid: Quickly find solutions and clarify doubts, maximizing your study efficiency.

Exam Readiness: Ideal for thorough revision and understanding the common types of word problems involving fractions that appear in exams.

Free and Convenient PDF: Available as a free, downloadable PDF, allowing for offline access and flexible study anytime, anywhere.